a man walk 3 km north and then 4 km east. find how far he is now from the starting position
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he walks 3km north and 4km East.
by Pythagoras theorem his displacement
=√(4^2+3^2)
=5km
by Pythagoras theorem his displacement
=√(4^2+3^2)
=5km
Answered by
1
Answer is 5km .
( by pythagoras theoram )
( by pythagoras theoram )
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