A man walk 50km tpwards east.then 40km towards north and then 20m towards west the magnitude of his displacement is
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Answer:
10 km is the magnitude of his displacement
10vkm is the answer
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QUESTION:-
A man walk 50km tpwards east.then 40km towards north and then 20m towards west the magnitude of his displacement is
EXPLANATION:-
(Kindly go through the attachment for the path of the object)
Displacement=AD
So we can calculate the displacement by phythagorus theorem
AD²=AE²+ED²
AD=?
AE=50-20
AE=30
ED=40
So,
AD²=30²+40²
AD²=900+1600
AD²=2500
AD=√2500
AD=50
So the displacement is 50 Km
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