Question

A man walked 2 mts
towards North, turned
West and walked 5 mts,
then turned North again
and walked 1 mts and
then turned East and
walked 9 kms. How far
away is he from the
starting point ?​

Answer 1

Answer:

Correct option is

A

5 metre

Let us consider a Cartesian plane thinking positive X-axis as South,

Negative x axis as North, Positive Y-axis as East and Negative as West.

A man walked along negative X-axis 3 m and then parallel to negative Y-axis he walked 2 m.

And then parallel to negative X-axis he walked 1 m and finally walked 5 m parallel to positive Y-axis and he has coordinates of (−4,3).

He makes right angle triangle with base AC=4, side AB=3 and hypotenuse BC.

∴ by Pythagoras theorem,

BC

2

=AB

2

+AC

2

⟹ BC

2

=3

2

+4

2

∴ BC=5.

Hence from origin he is at distance of 5 m.

Thus, option A is the correct.

solution

Explanation:

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Answer 2

Answer:

5m

Explanation:

please refer the photo for the answer.

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