A man walked 20m to cross a rectangular field diagonally if the length of the field is 16cm then the breadth of the field is
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Let a rectangular field ABCD
A/Q a man cross rectangular field diagonally and he had to walk 20m
So,Diagonal of Rectangle =20m
Length=16m (given)
We know that Each angle of a rectangle is 90°
ADC forms a right angled triangle
AC=16m(perpendicular)
AD=20m(Hypotenus)
CD=?(base)
According to Pythagorean Theorem
h2=b2+p2
(20)2=b2+(16)2
400=b2+256
b2=144
b=√144
b=12m
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A/Q a man cross rectangular field diagonally and he had to walk 20m
So,Diagonal of Rectangle =20m
Length=16m (given)
We know that Each angle of a rectangle is 90°
ADC forms a right angled triangle
AC=16m(perpendicular)
AD=20m(Hypotenus)
CD=?(base)
According to Pythagorean Theorem
h2=b2+p2
(20)2=b2+(16)2
400=b2+256
b2=144
b=√144
b=12m
plz mark as brainlist
Answered by
26
Hi ,
Dimensions of the rectangle ,
Length = l cm = 16cm
Diagonal = d cm = 20 cm
Breadth = b cm
b² = d² - l²
= ( 20 )² - ( 16 )²
= 400 - 256
= 144
b² = 144
b = √144
b = 12 cm
Therefore ,
Breadth of the rectangle = b = 12cm
I hope this helps you.
:)
Dimensions of the rectangle ,
Length = l cm = 16cm
Diagonal = d cm = 20 cm
Breadth = b cm
b² = d² - l²
= ( 20 )² - ( 16 )²
= 400 - 256
= 144
b² = 144
b = √144
b = 12 cm
Therefore ,
Breadth of the rectangle = b = 12cm
I hope this helps you.
:)
Aishwarya2005:
the diagonal is 20m not 20cm
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