A man walked 4 km towards North then 9 km towards South. What is his final position with respect to his initial position?
Answers
Answer:
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Step-by-step explanation:
A man walked 3 km towards the north, turned west and walked 2 km, then turned north again and walked 1 km and then turned east and walked 5 km. How far is he from his starting point?
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Q: A man walked 3 km towards the north, turned west and walked 2 km, then turned north again and walked 1 km and then turned east and walked 5 km. How far is he from his starting point?
Solution:
Starting point P.
1st travelling towards North
from point P to A=S1= 3 km
2nd travelling towards West
from A to B = S2= 2 km
3rd travelling towards North
from B to C = S3= 1 km
4th travelling towards East
from C to E1 =S4= 5 km
Joining all these points, finally we get a triangle from starting point P to the final destination E1 after covering a distance of 5 km to the East. The position of the traveller is now point E1, North-East (NE) position which is a diagonal measurement of the trianglar path from starting point P to E1.
Starting point P to North-East position E1:
Distance covered =d2= S1 + S3
d2 = 3 km + 1 km = 4 km
Length of triangluar side from West to East DE1:
d1 = DE1= S4 - S2 = 5 - 2 = 3 km
Using Pythagorean’s theorem:
d1^2 + d2^2 = PE1^2
4^2 + 3^2 = PE1^2
PE1^2 = 16 + 9 = 25
PE1 = 5 km
Answer:
The traveller is at a distance PE1 = 5 km from starting point to the end point E1 in the North-East direction.
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