Question

a man walked a distance of 40 km from a to b while returing his speed was 1km/hr more and as a result he took 1 hour less for the return journey find speed while returning​

Answer 1

Answer:

The distance will be 30km/hr and speed 5km/hr and 6km/ hr.Wrong posting...

Step-by-step explanation:

let take first speed x, then second speed x+1

time in 1st = 40/x, 2nd = 40/x+1

therefore, 40/x = 40/x+1+1

40/x - 40/x+1 = 1

40(x+1) - 40x/x(x+1) = 1

40/ x2+x = 1

40= x2+x

x2+x-40=0...

if distance = 30km

if x2+x-30=0

x2 +6x -5x -30=0

x(x+6) - 5(x+6) = 0

( x+6) (x-5) =0

x = 5