Question

a man walked around a path of semi circular garden of radius 14m.
a)what is the total distance traveled
b)what is the magnitude of displacement.​

Answer 1

Answer:

a. 44 m

b. 28m

Explanation:

the park is a semicircle

hence half of the circumference of a circle

1/2 x 2x 22/7 x r

1/2 x 2x 22/7 x 14

22 X 2

44 m is the distance travelled.

displacement is the shortest distance covered that is the diameter

therefore

2 x radius

2 x 14

28 m is the displacement.

Answer 2

Answer:

Distance travelled = 44 m

Displacement = 28 m

Explanation:

As per the provided information in the given question, we have :

• A man walked around a path of semi circular garden of radius 14m.

We are asked to calculate the total distance travelled and the magnitude of the displacement.

Calculating total distance travelled :

Suppose the body starts from point A. So, if man walked around a path of semi circular garden, it'll come to point B at last.

Thus, we can say that the perimeter of the semi-circular garden will be the total distance travelled.

→ Distance travelled = Perimeter of the semi-circular garden

→ Distance travelled = $\sf \dfrac{Perimeter_{(Garden)}}{2}$

→ Distance travelled = $\sf \dfrac{2\pi r}{2}$

→ Distance travelled = πr

→ Distance travelled = $\sf \dfrac{22}{7}$ × 14 m

→ Distance travelled = 22 × 2 m

→ Distance travelled = 44 m

∴ Distance travelled by him is 44 m.

Calculating displacement :

Displacement is the shortest distance from the initial position to final position. Here, initial position is A and final position is B. The shortest distance will be AB .

→ Displacement = AB

→ Displacement = Diameter of semi-circle

→ Displacement = 2 × Radius

→ Displacement = 2 × 14 m

→ Displacement = 28 m

∴ Magnitude of the displacement is 28 m.