A man walked certain distance he covered 2/3 of it a 4kmph and the remaining at 5kmph if the total time taken is 42 minutes then the total distance is
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Hey.
Here is the answer.
Let total distance be d
As, travelled 2/3 rd of d with 4kmph
so, time = (2x/3)/4 h
Rest 1/3 rd of d with 5kmph
so, time = (x/3)/5 h
As, total time = 42 min = 42/60 h
or, 42/60 = 2x/12 + x/15
or, 42/60 = (10x + 4x)/60
or, 42 = 14x
or, x = 42/14 = 3 km
Thanks.
Here is the answer.
Let total distance be d
As, travelled 2/3 rd of d with 4kmph
so, time = (2x/3)/4 h
Rest 1/3 rd of d with 5kmph
so, time = (x/3)/5 h
As, total time = 42 min = 42/60 h
or, 42/60 = 2x/12 + x/15
or, 42/60 = (10x + 4x)/60
or, 42 = 14x
or, x = 42/14 = 3 km
Thanks.
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