Question

A man walked up on stationary escalator in time T1 . On other days he remained stationary on the moving escalator and escalator took him up in time T2 the time taken by him to walk up on moving escalator will be

Answer 1

let length of escalator = s

v1 = s/t1 ( speed of man)

v2= s/t2 (speed of escalator)

time t when both moves = s/(v1+ v2)

= t1t2/(t1+t2)

Answer 2

Answer:

(t1 t2)/ t2 + t3

Explanation:

See the image