A man walkes 10km at an average
speed of 5 km/h. During the first hoursof walk, his speed is 6kmph. Find
a) The total time of walk?
b) Avevage speed during serond hour?
c )if he returns to the same position
find average velocity?
Answers
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Answer:
a)2hours
b)4kmph
c)0
Explanation:
i am not sure but I think it is the answer
a) total distance/average speed=10/5=2hours
b)total distance/total time=4/1=4kmph
c)the velocity will be 0 as he returned to the same place
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