Question

A man walking at 3/4 th of the speed
reaches his office late by 2 hours. What is the usual time?​

Answer 1

Answer:

6 hrs

Step-by-step explanation:

Let the normal speed be x.

The speed he walks with now is : 3/4x

Let the usual time be t.

The time he takes now is :

t + 2

The man walks the same distance every time.

Distance = speed × time

For both we have :

xt for normal speed.

3/4x(t + 2) for the reduced speed.

3/4tx + 1.5x

= 0.75tx + 1.5x

We equate the two as follows :

0.75tx + 1.5x = tx

1.5x = tx - 0.75tx

1.5x = 0.25tx

Divide through by 0.25x :

6 = t

Normal time is 6 hrs