Question

A man walking on a horizontal road with a speed of
4 km/h finds that rain drops are hitting his head
vertically. When he decreases his speed to 3 km/h,
he finds that rain drops are hitung his head at an
angle of 30° with the vertical. The magnitude of
Velocity of the rain drops w.rt.ground will be
with explanation plz.. ​

Answer 1

Answer:

1 km p h

Explanation:

because the man is running at the speed 4 km and the raindrops hit 3 km at the angle of 30 degree so the answer is 1 km hr

Answer 2

The magnitude of  velocity of the rain drops w.rt.ground will be 1.73 m/s.

Explanation:

It is given that,

Speed of man, $v_1=4\ km/h$

Decrease in speed, $v_2=3\ km/h$

The rain drops are hitting his head at an  angle of 30° with the vertical. Let v is the magnitude of  velocity of the rain drops w.rt.ground.

$tan\theta=\dfrac{v_2-v_1}{v}$

$v=\dfrac{v_2-v_1}{tan\theta}$

$v=\dfrac{3-4}{tan(30)}$

v = -1.73 m/s

|v| = 1.73 m/s

So, the magnitude of  velocity of the rain drops w.rt.ground will be 1.73 m/s. Hence, this is the required solution.

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Relative velocity

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