Question

A man walks 1 km to east and then he turns to south and walks 5 km. Again he turns to east and walks 2 km. After this he turns to north and walks 9 km. Now, how far is he from his starting point? 2 marks

Answer 1

5km is the answer



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Answer 2

Answer:

5 km

Step-by-step explanation:

we can find the distance using Pythagoras theorem

If u draw the diagram then u will see that a triangle can be formed by drawing  a horizontal line from the starting point to the 9 km path and then joining the end point of 9 km path to the starting point

hence the height of the triangle will be 9-5 =4 km and the base length will be 1+2=3 km

Now applying Pythagorean theorem:

let the distance be x^2

so :    3^2 + 4^2=x^2

9+16=x^2

25=x^2

x=$\sqrt{25}$

x=5km

The man is 5 km from the starting point