A Man walks 1 m east 2m north and 3m vertically upward direction then calculate displacement from starting point
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2 m north + 2m verticle total distance in north direction 5m
then using pythagores
x^2=5^2+1
x=5.02m (displacement)
then using pythagores
x^2=5^2+1
x=5.02m (displacement)
rahulbehera344:
your answer not matches with the real one right answer is under root 13
Sorry under root 14 is the answer
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