Question

a man walks 12 kilometre to the north and from there he walks to 15 km in the east and then from there to 19 kilometre in the west and then to 15 km to the South how much away how far is the man from the initial

Answer 1

Answer: 5 km

Step-by-step explanation:

= In ∆ ABC

using Pythagoras theorm

AC^2 = AB^2 + BC^2

AC^2 = 4×4 + 3×3

AC^2 = 16 + 9

AC^2 = 25

AC = 5 km