A man walks 12 km at a certain speed and then 8 km at 1 km/h .if the total time is 6 hour's
Answers
Answer:
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Answer:
36km
Step-by-step explanation:
let the original original speed of the man=x km/hr
the the schedule time of walking=y hrs
distance=yx km....... distance=time×speed according to first condition increased speed=(x+1/2)km/hr
reduce time=(y-1)hrs
distance=(x+1/2)(y-1) in in both case the distance are equal
:::> XY=xy+y/2-x-1/2
y-2x-1 <:::::> 2x-y=-1
according according to the second condition speed reduced=(x-1) km/hr
increased time=(y+3)hrs
distance distance =(x+1)(y+3)
xy-y+3x-3
in the both case distance are equal xy=xy-y+3x-3=3
subtract eq1 and eq2
x=4
put x=4 in eq1
2 x 4-y=-1
-y=-9=y=9
hence hence the speed of the man=4km/hr
the time of walking=9 hrs
the distance covered by man4×9=36km