Question

A man walks 12 km at a certain speed and then 8 km at 1 km/h .if the total time is 6 hour's.find his original speed​

Answer 1

answer

=> Formula Based Approach :

• Average speed = 2ab/(a + b) when distance is constant.

• = 2 x 8 x 6 / 14 = 48/7 kmph

• Time walked = 3 ½ hours.

• Total Distance covered = 3½ x 48/7 = 24 kms

=> Alternate Method :

• Speed inversely proportional to Time when Distance is constant.

• => If speed ratio = 8:6 then Time Ratio = 6:8 = 3:4

• => Total distance walked = 8 x 3.5x3/7 + 6 x 3.5 x 4/7

• = 12 + 12 = 24 kms

$hope \: its \: help \: u$