a man walks 12 steps in northern direction and turns left to walks 5 steps then returns to the same point by the shortest path .find distance travelled and displacement.Given each step is 0.3m
Answers
Answered by
70
the question can be solved by easy application of Pythagoras theorem.
perpendicular=
12x0.3=3.6 m
base=
5x0.3=1.5 m
calculating the hypotenuse, we get,
√(3.6)²+(1.5)²
√12.96+2.25
=3.9 m
∴displacement= 3.9 m
and,
distance=
3.6+1.5+3.9=9m
hope this helps!!
perpendicular=
12x0.3=3.6 m
base=
5x0.3=1.5 m
calculating the hypotenuse, we get,
√(3.6)²+(1.5)²
√12.96+2.25
=3.9 m
∴displacement= 3.9 m
and,
distance=
3.6+1.5+3.9=9m
hope this helps!!
Answered by
1
Answer:
9m
Explanation:
Distance covered = total distance travelled
=12+5+ shortest distance =17+
12
2
+5
2
=17+13=30 steps
Distance travelled =30×0.3 m=9 m
Hope it helps
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