A man walks 16 km in 2 hours.
rs
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Answered by
3
Answer:
be clear with the question plz
Answered by
1
Answer:
Let the original speed of the man=x km/hr
The schedule time of walking=y hrs.
∴ distance=yx km ..... Distance=Time×Speed
According to the first condition
increasedspeed=(x+
2
1
) km/hr
reducedtime=(y−1)hrs.
∴distance=(x+
2
1
)(y−1)
⇒xy+
2
y
−x−
2
1
In both case distance are equal
⇒xy=xy+
2
y
−x−
2
1
⇒y−2x−1⇔2x−y=−1 .......eq1
According to the second condition
reducedspeed=(x−1) km/hr
increasedtime=(y+3) hrs.
∴distance=(x−1)(y+3)
⇒xy−y+3x−3
In both case distance are equal
⇒xy=xy−y+3x−3⇒3x−y=3 ........eq2
Subtract eq 1 and eq2
⇒x=4
put x=4 in eq1
⇒2×4−y=−1
⇒−y=−9⇒y=9
Hence,The speed of the man=4 km/hr
The time of walking=9 hrs.
The distance covered by man 4×9=36 I'm
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