Question

A man walks 16 km in 2 hours.
rs​

Answer 1

Answer:

be clear with the question plz

Answer 2

Answer:

Let the original speed of the man=x km/hr

The schedule time of walking=y hrs.

∴ distance=yx km ..... Distance=Time×Speed

According to the first condition

increasedspeed=(x+

2

1

) km/hr

reducedtime=(y−1)hrs.

∴distance=(x+

2

1

)(y−1)

⇒xy+

2

y

−x−

2

1

In both case distance are equal

⇒xy=xy+

2

y

−x−

2

1

⇒y−2x−1⇔2x−y=−1 .......eq1

According to the second condition

reducedspeed=(x−1) km/hr

increasedtime=(y+3) hrs.

∴distance=(x−1)(y+3)

⇒xy−y+3x−3

In both case distance are equal

⇒xy=xy−y+3x−3⇒3x−y=3 ........eq2

Subtract eq 1 and eq2

⇒x=4

put x=4 in eq1

⇒2×4−y=−1

⇒−y=−9⇒y=9

Hence,The speed of the man=4 km/hr

The time of walking=9 hrs.

The distance covered by man 4×9=36 I'm