Question

a man walks 2a-b km due north from a fixed point O and then walks a distance of 3 A + 2B km due south what is his final position with regard to o.​

Answer 1

Answer:

a+3b

Step-by-step explanation:

First he walks to north: 2a-b

Then walks to south: 3a+2b

The difference of 3a+2b-(2a-b)=a+3b is the final position from the point O.

If the value of a+3b is positive, then the point is on north from the point O

If the value of a+3b is negative, then the point is on north from the point O

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