A man walks 2a km on the first day, 8 km on the second day and (a+3) km on the third day. How far does he walk in three days
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Step-by-step explanation:
according to the question,
first day = 2a km
second day = 8 km
third day = ( a + 3 )
Total distance he walk in three days
= 2a + 8 + ( a + 3 )
= 2a + 8 + a + 3
= 2a + a + 8 + 3
= 3a + 11
Therefore total distance covered in three days is 3a + 11 km
I hope this answer helps you
thank you
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