Question

A man walks 2a km on the first day, 8 km on the second day and (a+3) km on the third day. How far does he walk in three days​

Answer 1

Step-by-step explanation:

according to the question,

first day = 2a km

second day = 8 km

third day = ( a + 3 )

Total distance he walk in three days

= 2a + 8 + ( a + 3 )

= 2a + 8 + a + 3

= 2a + a + 8 + 3

= 3a + 11

Therefore total distance covered in three days is 3a + 11 km

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