Question

A man walks 2m due east and then 1.2 m due north. find his distance from starting point

Answer 1

distance is just the sum of all the length of path = 2 + 1.2 = 3.2 m
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Answer 2

Man walks 2m in East
and Then , he walks 1.2 m in North

If we make figure of this movement we'll obtain a right angled triangle which will get complete when we join starting and ending points of the man.

So, his distance from starting point will be given by Pythagorean theorem.

I.e. A²+B² = C²

So, here we have to find hypotenuse for the distance between starting and ending point.

So, let the distance or hypotenuse be x .

Using Pythagorean theorem-

x² = 2²+1.2²

or, x² = 4 + 1.44

or, x² = 5.44

or, √x² = √5.44

or, x = 2.33 m

Answer) His distance from starting point is 2.33m.