a man walks 3 km north and then 4 km east find how far is he now from the starting position
Answers
Answered by
18
5km...since the angle between both directions will be 90 degree...then by using Pythagoras theoram...u can get that
Answered by
36
By Pythagoras theorem, we know that
AC^2 = AB^2 + BC^2
= 4^2 + 3^2
= 16 + 9
= 25
AC = 5.
He has traveled 5km from the starting position.
AC^2 = AB^2 + BC^2
= 4^2 + 3^2
= 16 + 9
= 25
AC = 5.
He has traveled 5km from the starting position.
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