A man walks 3 km north and then 4 km east.How far he is from starting position
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using pythagoras therom..we solve this
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By using of Pythagoras theorem
AC^2 = AB^2+BC^2
4^2+3^2
16+9
25
AC = 5
The answer 5km
AC^2 = AB^2+BC^2
4^2+3^2
16+9
25
AC = 5
The answer 5km
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