A man walks 4 m towards east and then turns 60 degree to north of east
drashti3:
sooo what is your actual question??
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A is starting point. Man ckout the FAQ!
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Gate 2015 Aptitude Set 8 Q4
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asked Feb 15, 2016 in Numerical Ability by Akash Kanase Veteran (48.6k points)
retagged Jun 23, 2017 by Arjun912 views
Q.4 Mr. Vivek walks 6 meters North-east, then turns and walks 6 meters South-east, both at 60 degrees
to east. He further moves 2 meters South and 4 meters West. What is the straight distance in metres
between the point he started from and the point he finally reached?
(A) 2√2
(B) 2
(C) √2
(D) 1/√2
gate2015aptiset8 numerical-ability
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1 Answer
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answered May 15, 2016 by khushtak Boss (8.1kpoints)
option A 2√2

A is starting point. Vivek walks 6 meters North-east to point B, then turns and walks 6 meters South-east to the point C.He further moves 2 meters South to the point D and 4 meters West to the point E and E is end point.
as mentioned in fig. AC=6m and ED= FC = 4m
then AF=AC- FC = 6-4=2m
and EF= CD = 2m and angle AFE is right angle
by pythagoras theorem
AE2 = EF2 + AF2
AE2 = (4+4)
AE=2√2
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Use the google search bar on side panel. It searches through all previous GATE/other questions.
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Gate 2015 Aptitude Set 8 Q4
+1vote
912 views
asked Feb 15, 2016 in Numerical Ability by Akash Kanase Veteran (48.6k points)
retagged Jun 23, 2017 by Arjun912 views
Q.4 Mr. Vivek walks 6 meters North-east, then turns and walks 6 meters South-east, both at 60 degrees
to east. He further moves 2 meters South and 4 meters West. What is the straight distance in metres
between the point he started from and the point he finally reached?
(A) 2√2
(B) 2
(C) √2
(D) 1/√2
gate2015aptiset8 numerical-ability
Please log in or register to answer this question.
1 Answer
+4votes
answered May 15, 2016 by khushtak Boss (8.1kpoints)
option A 2√2

A is starting point. Vivek walks 6 meters North-east to point B, then turns and walks 6 meters South-east to the point C.He further moves 2 meters South to the point D and 4 meters West to the point E and E is end point.
as mentioned in fig. AC=6m and ED= FC = 4m
then AF=AC- FC = 6-4=2m
and EF= CD = 2m and angle AFE is right angle
by pythagoras theorem
AE2 = EF2 + AF2
AE2 = (4+4)
AE=2√2
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