A man walks 40km towards south and then turns right to walk 9km. What is the shortest distance between starting point and ending point.
50km
41km
49km
31km
Answers
Answered by
1
Answer:
41 km
Step-by-step explanation:
by Pythagoras theorem
hypotenuse^2 = (distance cover in South)^2+(distance cover in right)^2
h^2=40^2+9^2
h=√1600+81
h=√1681
h=41 km
Answered by
0
Answer:
Option A 50Km
Step-by-step explanation:
Drawing the diagram according to the given information,
By using Pythagoras’ theorem, the distance between A and B = √((40)2 + (30)2) = √2500 = 50 m
Hence, “50” is the correct answer
Similar questions