Question

A man walks 40m towards north and he turns his left and walked 40m. He then turns his left and walked 15m. He finally turns his right and walked 20m. What is the distance he is from starting point and in which direction?

Answer 1

Step-by-step explanation:

I hope u like the answer

Answer 2

Answer:

65 meters north west.

Step-by-step explanation:

Since, north is left to east, east is left to south, south is left to west and west is left to north,

Also, north is right to west, west is right to south, south is right to east and east is right to north,

Let O be the initial position of man,

Now, after going 40m towards north man's position is A,

Then after taking left and going 40m, his position is B,

After again going 15 m left his position is C,

Finally, his final position after going 20 m right, his position is D,

By making the diagram,

We observed,

D is north west to O.

Also, suppose L ∈ AO

Such that, AL = BC = 15 m,

⇒ LO = OA - AL = 40 - 15 = 25 m,

Also, DL = DC + CL = 20 + AB = 20 + 40 = 60 m,

By Pythagoras theorem,

$OD^2 = DL^2 + OL^2 = 60^2 + 25^2 = 3600 + 625 = 4225$

$\implies OD = 65\text{ m}$