Physics, asked by gorgeousgirlayesha, 11 months ago

A man walks 4m north then 3m East. the magnitude of displacement of man is​

Answers

Answered by Anubhab9493
9

Answer:

The magnitude of displacement=

whole root 4^2+3^2

that is = whole root 9+16

=whole root 25

=5

Hence the answer is 5m.

Plz mark it as the brainliest

Thanks a lot

Answered by nirman95
3

Given:

A man first walks 4 metres towards North and then 3 metres towards east.

To find:

Magnitude of displacement ?

Calculation:

  • Displacement is a vector quantity characterized by the shortest length between the starting and stopping point of the man.

Here, the shortest length can be calculated with PYTHAGORAS' THEOREM :

  • Let displacement be D :

D =  \sqrt{ {4}^{2} +  {3}^{2}  }

 \implies \: D =  \sqrt{16 + 9}

 \implies \: D =  \sqrt{25}

 \implies \: D =  5 \: metres

So, magnitude of displacement is 5 metres.

Attachments:
Similar questions