A man walks 4m north then 3m East. the magnitude of displacement of man is
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Answer:
The magnitude of displacement=
whole root 4^2+3^2
that is = whole root 9+16
=whole root 25
=5
Hence the answer is 5m.
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Given:
A man first walks 4 metres towards North and then 3 metres towards east.
To find:
Magnitude of displacement ?
Calculation:
- Displacement is a vector quantity characterized by the shortest length between the starting and stopping point of the man.
Here, the shortest length can be calculated with PYTHAGORAS' THEOREM :
- Let displacement be D :
So, magnitude of displacement is 5 metres.
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