Question

A man walks 4m north then 3m East. the magnitude of displacement of man is​

Answer 1

Answer:

The magnitude of displacement=

whole root 4^2+3^2

that is = whole root 9+16

=whole root 25

=5

Hence the answer is 5m.

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Answer 2

Given:

A man first walks 4 metres towards North and then 3 metres towards east.

To find:

Magnitude of displacement ?

Calculation:

• Displacement is a vector quantity characterized by the shortest length between the starting and stopping point of the man.

Here, the shortest length can be calculated with PYTHAGORAS' THEOREM :

• Let displacement be D :

$D = \sqrt{ {4}^{2} + {3}^{2} }$

$\implies \: D = \sqrt{16 + 9}$

$\implies \: D = \sqrt{25}$

$\implies \: D = 5 \: metres$

So, magnitude of displacement is 5 metres.