Question

a man walks 4m to the north, 12m to the west and finally climbs up a vertical pole up to a height of 3m.find the displacement and distance travelled by him is respectively.

Answer 1

distance= 12+4+3=19 m
displacement= by applying Pythagoras theorem √12^2+4^2=√160=12.649

Answer 2

Heya....!!!

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Given in the question :-

=> a man walks : 4 m North ( that is j^ ( j cap ) ) , 12 m west ( that is i^ ) and then finally 3 upwards that is ( z^ )

His displacement will be :-

⇒$\sqrt{ 12^2 + 3^2 + 4^2 } ➡ \sqrt{ 169 } = 13$

⇒ Displacement is 13 m

Distance is simply the total path => 12 + 4 + 3 = 19 m

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