A man walks 4m towards north then 3m towards east and there he climbs a pole of 12m height then the total displacement by man is
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Rohit710 Physics Newton
Heya....!!!
______________________
Given in the question :-
=> a man walks : 4 m North ( that is j^ ( j cap ) ) , 12 m west ( that is i^ ) and then finally 3 upwards that is ( z^ )
His displacement will be :-
⇒
⇒ Displacement is 13 m
Distance is simply the total path => 12 + 4 + 3 = 19 m
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Answer:13m
Step-by-step explanation:
Displacement d=4i+3j+12k
D=√(4square+3square+12square)
d=√169
d=13m
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