Question

A man walks 5 1/5 km towards north, 6 1/6 km towards east and 10 1/10 km towards south. Find the total distance travelled by him.​

Answer 1

Answer:

914/30

Step-by-step explanation:

A man walks in north towards = 51/5 km

A man walks in east towards = 61/6 km

A man walks in south towards = 10 1/10 or 101/10

Then,

= 51/5+61/6+101/10 (L.C.M of 5,6,10 = 30)

= 51×6/30+61×5/30+101×3/30

= 306/30+305/30+303/30

= 306+305+303/30

= 914/30

Hence, the total distance travelled by man is 914/30.