Question

A man walks 5 m towards east and turns right and moves 12 m the magnitude of his displacement is 10 m 20 m 15 m13 m​

Answer 1

Explanation:

As per the provided information in the given question, we have :

• A man walks 5 m towards east and turns right and moves 12 m.

We are asked to calculate the magnitude of his displacement (s).

Before commencing the steps, let's first understand what is meant by displacement.

Displacement is the shortest distance between the initial and final position of the body, in a particular direction. The shortest distance between the initial and final position of the body is always a straight line. It is denoted by s and its SI unit is m(metre).

Now, coming back to the question. Here, the body covers 5 m towards east and turns right and moves 12 m. That means, he firstly covers 5 m in East and after turning he covers 12 m in South. South is the direction right to East.

We made a straight line between its final and it's initial position, which is its displacement. (Refer to the attachment.)

By using pythagoras property,

$\\ \longrightarrow \sf{\quad { (12 \; m)^2 + (5 \; m)^2 = (s)^2 }}$

Here, s is denoting displacement.

$\\ \longrightarrow \sf{\quad { 144 \; m^2 + 25\; m^2 = (s)^2 }}$

$\\ \longrightarrow \sf{\quad { 169 \; m^2 = (s)^2 }}$

$\\ \longrightarrow \sf{\quad { \sqrt{169 \; m^2} = s }}$

$\\ \longrightarrow \sf{\quad { 13 \; m = s }}$

$\\ \longrightarrow \bf{\quad { \underline{13 \; m = Displacement }}}$

Therefore, 13 m is the displacement.