Question

a man walks 5 metre towards east and turns right and moves 12 metre the magnitude of his displacement is​

Answer 1

Let us take the initial point as A

The person walks 5 metres from A towards east, and turns at point B to his right, and walks 12 metres till point C.

Here, this makes a right angle triangle as shown in the attachment :

According to Pythagoras theorem of a right triangle,

${AC}^{2} = {AB}^{2} + {BC}^{2}$

In this case, AB = 5 metres.

BC = 12 metres.

Hence, the displacement in this case is AC.

${AC}^{2} = {AB}^{2} + {BC}^{2}$

${AC}^{2} = {5}^{2} + {12}^{2}$

${AC}^{2} = 25 + 144$

${AC}^{2} = 169$

$AC \: = \sqrt{169}$

$AC \: = 13$

$\therefore \: displacement \: = 13 \: metres$

Hope it is clear :-)