a man walks 5m in the northern direction and turns left to move 12m. what is the distance and displacement travelled by the man
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hi and here's is your answer
distance 12m + 5m = 17 m
displacement = if you try to make diagram you'll see that the final point to initial point is a right angled triangle, so
displacement = shortest route and you'll see that hypotenuse is the shortest route so find hypotenuse using Pythagoras theorem
(H)² = (p)² + (b)²
(H)² = 12² + 5² (i set these values by if you see the diagram you made distance travelled till north is b and after left turn it's p
(H)² = 144 + 25
(H)² = 169
(H) = 13
key = p = perpendicular or distance after left turn
b = base or distance before left turn
h = displacement or hypotenuse
hope it's helpful for you
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