Physics, asked by manasvideokar, 8 months ago

a man walks 5m in the northern direction and turns left to move 12m. what is the distance and displacement travelled by the man

Answers

Answered by Anonymous
0

Explanation:

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Answered by chauhanvarun2001
7

Answer:

hi and here's is your answer

distance 12m + 5m = 17 m

displacement = if you try to make diagram you'll see that the final point to initial point is a right angled triangle, so

displacement = shortest route  and you'll see that hypotenuse is the shortest route so find hypotenuse using Pythagoras theorem

(H)² = (p)² + (b)²

(H)² = 12² + 5²       (i set these values by if you see the diagram you made                        distance travelled till north is b and after left turn it's p

(H)² = 144 + 25

(H)² = 169

(H) = 13

key = p = perpendicular or distance after left turn

b = base or distance before left turn

h = displacement or hypotenuse

hope it's helpful for you

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