A man walks 5m towards west and 12m towards north and the 7m vertically upwards. Calculate the magnitudevof sum of their displacement?
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Answered by
9
Answer:
- A man walks 5 m towars West
- From there he walks 12 m north
- Finally he takes a vertical walk of about 7 m
- Displacement = ?
Diagram
- So here from the diagram we shall see that the path of the man forms a triangle and so tje shortest distance to reach the final position from the initial position will be the length of the Hypothenuse
- First we shall find the distance between A & B
- Vertical = North direction
- The man starts from C and stops at A so as we saw the smallest path to reach A will be the Hypothenuse. We know that ABC is a right angled triangle right angled at B so on using the Pythagoras theorem we shall find the length of AC which will be our Answer!!
⨳ Displacement is a vector quantity that has both magnitude and direction
⨳ Displacement is the shortest path between two lines which is a straight line
⨳ Displacement ≤ Distance
⨳ Distance can never be greater than Displacement
Answered by
52
Given:
- Man walks 5m towards West
- Then, he walks 12m towards North
- And then 7m vertically upwards
Find:
- What will be its Displacement
Solution:
⋆ CB = Distance towards North + Distance vertically upwards
↣ CB = 12 + 7
↣ CB = 19m
Now, by using pythogoras theorem
⤑
⤑
where,
- BC = 19m
- AB = 5m
So,
⪼
⪼
⪼
⪼
⪼
⪼
⪼
______________________
Therefore, Displacement = 19.6m
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