Question

A man walks 6 km at a speed of 112kmph, runs 8 km at a speed of 2 kmph and goes by bus another 32 km. Speed of the bus is 8 kmph. Find the average speed of the man in kmph.

Answer 1

$\huge\boxed{\texttt{\fcolorbox{Red}{aqua}{Hey Mate!!!!}}}$

$<b><i><font face= Copper black size=4 color=blue>$
Here is your answer.
A man walk a distance 6 km
Speed = 112 km/ hr
so Time Taken= Distance/Speed
$= \frac{6}{112} \\ = \frac{3}{56} \: hrs$
Now Man runs a distance = 8 km
at speed = 2 km/ hr
Time Taken is
$= \frac{8}{2} \\ = 4 \: hrs$
Now Man goes by Bus a distance = 32 km
at speed = 8 km/ hr
Time Taken is
$= \frac{32}{8} \\ = 4 \: hrs$
So
Total Distance he cover is
= 6+8+32
= 46 km
Total Time Taken is
$= \frac{3}{56} + 4 + 4 \\ = \frac{3}{56} + 8 \\ = \frac{3 + 448}{56} \\ = \frac{451}{56} hr$
Average Speed = Total Distance/Total Time
$= \frac{46}{ \frac{451}{56} } \\ = 46 \times \frac{56}{451} \\ = 5.96 \: km \: per \: hr$
So The average speed of man is 5.96 km/hr
or 6 km / hr
$\large{\red{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\underline{\underline{\underline{Hope\:it\: helps\: you}}}}}}}}}}}}}}}$

Answer 2

Hey mate ^_^

=======
Answer:
=======

Man walked 6 km at 1.5 kmph.

Again he walked 8 km at speed of 2 kmph and 40 km at a speed of 8kmph

Now,

Time taken individually:

$\frac{6}{1.5} = 4 \: m$

$\frac{8}{2} = 4 \: m$

$\frac{40}{8} = 5 \: m$

Average speed of man $= \frac{total \: distance}{total \: time}$

$\frac{54}{13} = 4 \frac{2}{13}$

Therefore,

The average speed of the man in kmph is $4 \frac{2}{13}$

#Be Brainly❤️