Physics, asked by JEM123, 11 months ago

A man walks 6 km due east and then walks 8 km due north and stops. The magnitude of displacement in Km is ​

Answers

Answered by Anonymous
14

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Answered by kurmirubikumari
3

Answer:

10

Explanation:

North and east are perpendicular.

Displacement is shotest distance.so.by joing get shotest distance.

Now apply phytagoros tripet

(6^2 +8^2) whole root =√100= 10

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