Question

a man walks 6 km towards north for which he takes 1 hr . he rest for half and hour then he walk towards south 10 km. find the distance covered and displacemnt

Answer 1

Answer:

Distance - 16 km Displacement - 4 km

Explanation:

Distance = Total length covered

               = 6km + 10 km

               = 16km

Displacement = shortest distance possible(refer to the attachment for a                    

                                                                              better understanding)

Let the starting point of the man be A. The rest point be B and the finish point be C.

To get the displacement you should subtract the first distance i.e D1 from the second distance D2.

Displacement = D2 - D1

                       = 10km - 6km

                       = 4km

Hope this answer was useful to you.

                     

                                   

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Answer 2

He travels totally for 6+10=16 km
Thus distance covered = 16 km

Now, displacement:

Lets initial direction of motion be south

Thus 6km north = -6
And 10km south = +10

After travelling 6km north, he travels 10km south starting from the same point
= -6 + 10
=4 km is the displacement