Question

A man walks 70m in 20s then turn back then walk 30 m towards the starting point in 15s find average speed and average velocity.

Answer 1

$\huge\underline\blue{\sf Answer:}$

$\red{\boxed{\sf Average\:Speed(V_{speed})=2.85m/s }}$

$\red{\boxed{\sf Average\: Velocity (V_{Velocity})=1.14m/s }}$

$\huge\underline\blue{\sf Solution:}$

$\large\underline\pink{\sf Given: }$

• Distance $\sf{(s_1)=70m}$

• Time $\sf{(t_1)=20s}$

• Distance $\sf{(s_2)=30m}$

• Time $\sf{(t_2)=15s}$

$\large\underline\pink{\sf To\:Find: }$

• Average Speed $\sf{(V_{speed})}$= ?

• Average Velocity $\sf{(V_{Velocity})=?}$

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${\boxed{\sf Average\:Speed(V_{speed})=\frac{Distance}{Time} }}$

$\large\implies{\sf \frac{70+30}{20+15}}$

$\large\implies{\sf \frac{100}{35} }$

$\large\implies{\sf 2.85}$

$\red{\boxed{\sf Average\:Speed(V_{speed})=2.85m/s }}$

${\boxed{\sf Average\: Velocity (V_{Velocity})=\frac{Displacement}{Time} }}$

$\large\implies{\sf \frac{70-30}{20+15} }$

$\large\implies{\sf \frac{40}{35}}$

$\large\implies{\sf 1.14}$

$\red{\boxed{\sf Average\: Velocity (V_{Velocity})=1.14m/s }}$