Question

A man walks 8 km to north 5km to east and 4km to north. how far is he from the starting point

Answer 1

ANSWER:

13 Km

.

EXPLANATION:

We are use the Pythagoras' Theorem to find the shortest ( Diagonal) distance from starting point to the end point.

.

Total distance traveled northwards = 8 + 4 = 12 km

Total distance traveled eastwards = 5 km

.

Find the diagonal distance from the start point to the end point:

a² + b² = c²

12² + 5 ² = c²

c² = 144 + 25

c² = 169

c = √169

c = 13 km

.

Answer: He is 13 km away from the starting point.

.

Answer 2

Answer:

13kilometers.

Step-by-step explanation:

distance towards north is 8 + 4 = 12km. and towrds east is 5km.

p^2 + q^2 = r^2

12² + 5 ² = r^2

r^2 = 144 + 25

r^2 = 169

r = √169

r = 13 km