A man walks 8 metres towards east and then 6 metres towards north is magnitude of displacement is
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Answer:
when we draw the diagram of this question we get a right angle triangle.
So,by Pythagoras theorem.we get
let,
perpendicular=6m
base=8m
h^2=p^2+b^2
h=√(6)^2+(8)^2
h=√36+64
h=√100
h=10m
Hence,the displacement is 10m
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