Physics, asked by piyush764, 1 year ago

a man walks 80 metre in 20 seconds and then turns back and walks 50m towards the charging point in 30 seconds find the average velocity
a. 0.50m/s
b. 0.60m/s
c. 54m/s
d. 60 m/s

Answers

Answered by shtushar3601
18

Always remember Champ!

Average Velocity= Change in Position/ Total Time

Here, he went 80m and then came back 50m, his Total position change was 80-50m= 30m

He took time 30s+20s= 50s

Avg. Velocity= 30/50= 0.6m/s

Correct Answer would be Option (b)!


piyush764: thanks
Answered by muscardinus
6

The average velocity of the man is 0.6 m/s.

Explanation:

In this case, it is given that a man went 80 m and then came back 50 m. The total distance covered by the man is 80 - 50 = 30 m

He takes total time of 30+20 = 50 seconds.

The average velocity of the man is given by the total distance covered divided by total time taken. It is given by :

v=\dfrac{d}{t}

v=\dfrac{30\ m}{50\ s}

v = 0.6 m/s

So, the average velocity of the man is 0.6 m/s. Hence, this is the required solution.

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Average velocity

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