Question

A man walks 8m towards east to reach point P He turns to his right and walks 5m to reach point Q. Then, he turns to his left and walks 9m to
reach point R and he turns to his right and walks 11m to reach point S. Finally he turns to his right and walks 20m to reach point T What is the
distance between starting point and Q?
Select one
O A 189
O B. 13km
O C. 9m
O D. 163​

Answer 1

Answer:

13m

Step-by-step explanation:

because in question it is said that what is the distance between starting point and Q.

.: 8m+5m=13m

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Answer 2

Concept

The pythagoras theorem says that if a triangle is right angled then the square of its hypotenuse will be equal to the sum of the squares of its base and height.

Given

PQ=5 m

QR=9m

RS=11 m

ST=20m

To find

The distance between the starting point and Q.

Explanation

let the starting point be A .If we carefully plots the points by reading the question, we found that there is a right angled triangle APQ where AP is base PQ is perpendicular and AQ is the hypotenuse and

AQ=$\sqrt{AP^{2}+PQ^{2} }$

=$\sqrt{5^{2}+8^{2} }$

=$\sqrt{89}$

=9.43

=9 m APPROX

Hence the right option is C.

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