Question

a man walks (9x+5) km due east , then 2/3x km due west and finally (5x-1/3) km due east. How far is he from the starting point.​

Answer 1

Answer:

41x/3  + 5 km

Step-by-step explanation:

A man walks(9x+5)km due east

=>east Direction = 9x + 5 km

then 2x/3 km due west

=> East Direct = -2x/3  km

finally (5x_1/3)km due east

=> East Direction = 16x/3  km E

Total Distance in east direction = 9x + 5 - 2x/3  + 16x/3

= 9x + 5 + 14x/3

= 41x/3  + 5 km