A man walks(9x+5)km due east, then 2/3xkm due west and finally (5x_1/3)km due east. How far is he from the starting point?
Answers
Answered by
7
Answer:
41x/3 + 5 km
Step-by-step explanation:
A man walks(9x+5)km due east
=>east Direction = 9x + 5 km
then 2x/3 km due west
=> East Direct = -2x/3 km
finally (5x_1/3)km due east
=> East Direction = 16x/3 km E
Total Distance in east direction = 9x + 5 - 2x/3 + 16x/3
= 9x + 5 + 14x/3
= 41x/3 + 5 km
Answered by
4
Step-by-step explanation:
wrong answer of above ☝☝
correct is 40/3x + 14/3
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