a man walks a distance of 48km.with his normal speed in a specific time.if he walks 2km .per hour faster than his normal speed,he will perform the journey in 4hrs less than earlier time.find his normal speed
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Answer:
4kmph
Step-by-step explanation:
man norman speed =V
distance d=48km
1) normal time taken to man to covers 48km =t
2) if he walks 2kmph faster than nomal speed(V+2),
then time taken to cover the same distance = t-4
from 1, t=48/V..................(3)
from 2, t-4=48/(V+2)................(4)
by solving equation 3 & 4
we get V*V+2V-24=0
V= 4, -6
THE NORMAL SPEED OF MAN IS (V)=4KMPH
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