Question

A man walks along the border of a rectangular ground from one corner to the diagonally opposite corner, Find the distance and displacement if the ground is 70m wide and 240m long​

Answer 1

Answer

Displacement is 250 m and Distance is 310 m

Explanation:

For Distance simply add the 2 number

70+240 = 310

Let the first point be A, second be B and diagonally opposite corner be C

Length is 240m

Breadth is 70m

We know that angles of rectangle are 90 degree      

Using Pythagoras theorem in Triangle ABC

$AC^{2} = AB^{2} + BC^{2}$

$AC = \sqrt{4900+57600}$

$AC = 250$ m

This is the displacement.

Answer 2

Answer:

Distance  = 310 m

Displacement = 250 m

Explanation:

♢ Given :

• The man is walking along a rectangular ground .
• Length of the ground in 240 m
• breadth of the ground is 70 m

♢ Basic Concept Used :

• Distance is the total length travelled by a body  .
• Displacement is a straight line connecting initial and final position .

before we go ahead , take a look at the attached figure .

I've tried showing that the diagonal is the displacement . M1 means man at first case and M2 shows man at second case (as its already given in question that man travelled diagonally opposite corner)

♤ Procedure

So we get to know that

the total Distance travelled will be length + breadth ie . 240 + 70 = 310 m

☆ Total Distance travelled = 310m

Displacement will be the path along that diagonal because it connects initial and final position .

here is the place Pythagoras theorem comes to our rescue .

(240)^2 + (70)^2 = (displacement)^2

57600 + 4900 = 62500

displacement = root 62500

☆ displacemt = 250m ☆

¤ Note : Displacement can never ever be greater than distance travelled .