A man walks at 1m/s for 60 minutes he takes rest for 20 minutes and then walks at a seed of 1m/s for 60 minutes find his average speed
Answers
Explanation:
Total Distance = 1 × 3600 + 1 × 3600
= 7200 metersTotal Time = 120 x 60 + 20 x 60 minutes
Average Speed = Total Distance / Total Time = 7200/8400 = 6/7 m/s
this is the required Average Speed
hope this may help you
Answer:
Total Distance = 1 × 3600 + 1 × 3600
= 7200 metersTotal Time = 120 x 60 + 20 x 60 minutes
Average Speed = Total Distance / Total Time = 7200/8400 = 6/7 m/s
this is the required Average Speed
Explanation:
Given---
Distance covered by the man in 1 second. = 1 m.
∴ Distance covered by the man in 60 min.= 1 × 60 × 60
= 3600 m.
Now,
Distance covered by the man is the 20 min. = 0 m.
[Since boy is taking the rest]
Distance covered by the man in last 60 min. = 1 m × 60 × 60
= 3600 m.
∴ Total Distance Covered by the man = 3600 + 0 + 3600
= 7200 m.
Total Time taken by the man = 60 min. + 20 min. + 60 min.
= 140 min.
= 140 × 60 seconds.
= 8400 seconds.