Question

A man walks at 40kmph and reaches the distance in 10 min less than that of usual . By walking at 60 kmph he reaches 10 minutes earlier. The distance covered by him is.?

Answer 1

distance= 4 km

short cut method

d=S1*S2/S1-S2*Difference of time

40*60/20*(+10-(-10))/60

240/20*20/60

12*1/3

4km

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