Math, asked by dashbabita2015, 1 month ago

A man walks at 6 km/h and runs at 8 km/h. He covers 6 km in 50 min partly by running
and partly by walking.
(i) For how long did he walk? (ii) What distance did he cover walking?​

Answers

Answered by cheemtu
2

Answer:

When he walks,

Speed = 6 km/h

Distance = x km ( suppose)

Thus, the time taken by him in walking = \frac{x}{6}

6

x

hours,

( Because, time = distance/speed )

Now, when he runs,

Speed = 8 km/h

Distance = (6-x) km, ( Because, he covers 6 km partly by walking and partly by running )

Thus, the time taken by him in walking = \frac{(6-x)}{8}

8

(6−x)

hours,

Since, According to the question,

The total time taken by him in both walking and running = 50 minutes

⇒ \frac{x}{6}+\frac{6-x}{8}=\frac{50}{60}

6

x

+

8

6−x

=

60

50

⇒ \frac{4x+18-3x}{24}=\frac{5}{6}

24

4x+18−3x

=

6

5

⇒ \frac{x+18}{24}=\frac{5}{6}

24

x+18

=

6

5

⇒ 6x+108=120\implies 6x=12 \implies x =26x+108=120⟹6x=12⟹x=2

Thus, The distance he covers in walking = 2 km,

And, the distance he covers in running = 6 - 2 = 4 km.

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